
Question #1aa66 + Example - Socratic
The sentence "Van has come." is grammatically correct IF the noun "Van" is the name of a person. A proper noun is not usually preceded by an article. If the noun "van' is a common noun, a word for a …
Question #9f38f - Socratic
L=1.01m Parameters L = ? g = 10ms^-2 pi = 22/7 T = 2sec From S.H.M T = 2pisqrt (L/g) Making L the subject of formula.. T = 2pisqrt (L/g) Divide both sides by color ...
How does "chlorate" oxidize hydrazine to give NO and ... - Socratic
3N_2H_4(g) + 4ClO_3^(-)(aq) rarr 6NO(g) + 6H_2O(l) + 4Cl^(-)(aq) This is one equation for the oxidation of hydrazine to nitrous oxide. It also accords with your question. Quite clearly, the equation …
Question #0e55c - Socratic
Find the real roots of 256/2401 then consider the imaginary values that correspond to each of the real roots. First we consider only the two real roots, which we can find but taking the 4th root of 256/2401: …
Suppose you ran this sequence of reaction starting with 8.0 g of ...
Sep 6, 2015 · Suppose you ran this sequence of reaction starting with 8.0 g of benzoic acid, excess methanol, and excess phenyl magnesium bromide.What would be the expected theoretical yield of …
Question #6d4d4 - Socratic
3+i" or " -3-i "let " sqrt(8+6i)=a+bilarr" square both sides" rArr8+6i=(a+bi)^2=a^2-b^2+2abi "equating the coefficients of real/imaginary parts" a^2-b^2=8to(1) 2ab=6rArrb=3/ato(2) "substitute " b=3/a" in " (1) …
Why does South Sudan want to be independent from the ... - Socratic
May 4, 2017 · People from South Sudan are often from various African Racial/Religious groups (christian mostly, using languages from Chad) as opposed to a Arab Racial/Religious group in the …
How do you solve #-10z ^ { 2} = 11z - 6#? - Socratic
(2/5) and (-3/2) f(z) = 10z^2 + 11z - 6 = 0 Solve it by the new transforming method (Socratic Search) Method. First, find 2 real roots of the transformed equation. f'(z) = z^2 + 11z - 60 = 0. Next divide …
Question #34056 - Socratic
sqrt3" sq.units." By the Cosine Rule, cosA=(b^2+c^2-a^2)/(2bc), and, cosB=(a^2+c^2_b^2)/(2ac). :. cosA/a=cosB/b".........[Given]," rArr (b^2+c^2-a^2)/cancel(2abc)=(a ...
Arnoldo B. on Socratic
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